Methods of establishing minimum allowable
thickness range from the highly complex to the simple. With the average heater,
the operating pressure and temperature are known only for the heater inlet and
outlet. The pressure and temperature at intermediate points is typically
estimated by calculations or measured with pressure gauges and thermocouples
installed at appropriate locations.
The metal temperature governs the allowable
working stress for tube materials. Therefore, for a given tube size and a given
operating pressure, the minimum allowable thickness varies with the tube
temperature. Tube temperature is an important parameter to know, especially at
the highest levels of the normal operating condition.
API Std. 530 gives extensive information on
the calculation of required wall thickness of new tubes (carbon steel and alloy
tubes) for petroleum refinery heaters. The procedures given are appropriate for
designing tubes or checking existing tubes in both corrosive and non-corrosive
services.
Many methods, including those involving tube
skin thermocouples, infrared cameras, infrared pyrometers, and optical
pyrometers, are available to determine the metal temperature of a tube. A
simple method is to estimate the metal temperature from the operating fluid
temperature and then adjust the temperature estimate based on the location of
the tube in the heater—the skin temperatures on a tube closer to the flame or
nearer the heater outlet will be hotter than one at the heater inlet.
Under certain conditions, the methods
described in the preceding text may result in a thickness that is too small for
practical purposes. The minimum allowable thickness must be great enough to
give the tube sufficient structural strength to prevent sagging between
supports and to withstand upset operating conditions. For this reason, it may
be appropriate to add some amount based on experience to the calculated minimum
allowable thickness and to use this greater thickness as the limit at which a
tube should be replaced. Generally, this would be about 0.125 in. (0.32 cm) in
these cases.
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